Fix maximum recursion error + catch hardcoded password in define()
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4f985f9709
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e3b1d7fb3c
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@ -2,7 +2,8 @@
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[![Python 3.4+](https://img.shields.io/badge/python-3.4+-blue.svg)](https://www.python.org/downloads/release/python-360/)
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Basic script to detect vulnerabilities into a PHP source code
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Basic script to detect vulnerabilities into a PHP source code, it is using Regular Expression to find sinkholes.
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```bash
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╭─ 👻 swissky@crashlab: ~/Github/PHP_Code_Static_Analysis ‹master*›
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╰─$ python index.py --dir test
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16
detection.py
16
detection.py
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@ -11,6 +11,7 @@ result_files = 0
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# Analyse the source code of a single page
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def analysis(path, plain):
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global result_count
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global result_files
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result_files += 1
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with open(path, 'r', encoding='utf-8', errors='replace') as content_file:
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@ -22,21 +23,23 @@ def analysis(path, plain):
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# Hardcoded credentials (work as an exception, it's not function based)
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credz = ['pass', 'secret', 'token', 'pwd']
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for credential in credz:
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content_pure = content.replace(' ', '')
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credential += ".*?=[\"|'][^\\$]+[\"|']"
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regex = re.compile("\\$" + credential, re.I)
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# detect all variables
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regex_var_detect = "\$[\w\s]+\s?=\s?[\"|'].*[\"|']|define\([\"|'].*[\"|']"
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regex = re.compile(regex_var_detect , re.I)
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matches = regex.findall(content_pure)
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# If we find a variable with a constant for a given indicator
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for vuln_content in matches:
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if credential in vuln_content.lower():
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payload = ["", "Hardcoded Credential", []]
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# Get the line
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line_vuln = -1
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splitted_content = content.split('\n')
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for i in range(len(splitted_content)):
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regex = re.compile("\\$" + credential + ".*?=", re.I)
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regex = re.compile(regex_var_detect, re.I)
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matches = regex.findall(splitted_content[i])
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if len(matches) > 0:
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line_vuln = i
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@ -45,6 +48,8 @@ def analysis(path, plain):
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line = str(line_vuln)
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occurence = 1
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result_count = result_count + 1
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display(
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path,
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payload,
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@ -97,7 +102,6 @@ def analysis(path, plain):
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false_positive = True
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if not false_positive:
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global result_count
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result_count = result_count + 1
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display(path, payload, vuln_content, line_vuln, declaration_text, line, vulnerable_var[1], occurence, plain)
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@ -111,7 +115,7 @@ def recursive(dir, progress, plain):
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try:
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for name in os.listdir(dir):
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print('\tAnalyzing : ' + progress_indicator * progress + '\r'),
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print('\tAnalyzing : ' + progress_indicator * progress + '\r', end="\r"),
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# Targetting only PHP Files
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if os.path.isfile(os.path.join(dir, name)):
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13
index.py
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index.py
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@ -1,22 +1,23 @@
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#!/usr/bin/python
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# -*- coding: utf-8 -*-
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# Author : Swissky
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# How to use : python index.py --dir test
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# Educational purpose only !
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# TODO afficher toutes les modifications de la variable
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import sys
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import argparse
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from detection import *
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if __name__ == "__main__":
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parser = argparse.ArgumentParser()
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parser.add_argument('--dir', action='store', dest='dir', help="Directory to analyse")
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parser.add_argument('--plain', action='store_true', dest='plain', help="No color in output")
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results = parser.parse_args()
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if results.dir is not None:
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# default recursion is limited to 1000
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# since we browse files recursively,
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# we need to set an higher threshold
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sys.setrecursionlimit(1000000)
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print(""" (`-') <-. (`-')_ _(`-') (`-') _
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_(OO ) .-> <-. \\( OO) ) .-> _ .-> ( (OO ).-> ( OO).-/
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,--.(_/,-.\\,--.(,--. ,--. ) ,--./ ,--/ ,--.' ,-.\\-,-----.(`-')----. \\ .'_ (,------.
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@ -1,5 +1,8 @@
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<?php
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// Fake configuration (include follow ?)
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define("USERNAME", "admin");
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define("PASSWORD", "pwd123*");
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// Fake configuration (include follow ?)
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$DB_HOST = "localhost";
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$DB_NAME = "securitychalls";
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$DB_USER = "admin";
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@ -11,4 +14,6 @@
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$pwd = "mysuper_cr3dz";
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$pass = $pwd.$token;
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$Pass = "case!nsenSitiveP@ss"
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?>
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?>
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