metasploit-framework/lib/net/dns
Tod Beardsley 2bfe5ee5a6 Add a ResolverError class 2012-09-04 19:20:31 -05:00
..
names Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
resolver Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
rr Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
README Import the Net-DNS library 2008-07-23 17:32:05 +00:00
dns.rb Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
header.rb Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
packet.rb Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
question.rb Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00
resolver.rb Add a ResolverError class 2012-09-04 19:20:31 -05:00
rr.rb Mark all libraries as defaulting to 8-bit strings 2012-06-29 00:18:28 -05:00

README

Net::DNS README
============

  This is a port of the Perl Net::DNS module, written by Michael Fuhr
and now currently maintained by Olaf Kolkman (www.net-dns.org). It
keeps the same interfaces and function names, although has a bit
improved OO and some other stuff.
It can be used to query DNS servers for various kind of records, perform
zone transfer and dynamic updates. It has even a class for acting as a
nameserver.
This version is quite incomplete. You can use it as a resolver.


Requirements
------------

  * Ruby 1.6


Install
-------

  De-compress archive and enter its top directory.
  Then type:

   ($ su)
    # ruby setup.rb

  These simple step installs this program under the default
  location of Ruby libraries.  You can also install files into
  your favorite directory by supplying setup.rb some options.
  Try "ruby setup.rb --help".


Usage
-----

  Have a look on the manual pages.
  In doc/ you will find many useful documents too.


License
-------

  Net::DNS is distributed under the same license Ruby is.


Author
------

  See AUTHORS


#	$Id: README,v 1.2 2005/06/17 15:11:18 bluemonk Exp $