use bind for partial application of power set function
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e8bb9e264d
commit
951568ce22
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@ -70,7 +70,7 @@ class SetOps {
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"Set Difference": this.runSetDifference,
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"Symmetric Difference": this.runSymmetricDifference,
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"Cartesian Product": this.runCartesianProduct,
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"Power Set": this.runPowerSet(itemDelimiter),
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"Power Set": this.runPowerSet.bind(undefined, itemDelimiter),
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}[operation]
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.apply(this, sets.map(s => s.split(itemDelimiter)));
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@ -113,6 +113,7 @@ class SetOps {
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/**
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* Get the intersection of the two sets.
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*
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* @param {Object[]} a
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* @param {Object[]} b
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* @returns {Object[]}
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@ -125,6 +126,7 @@ class SetOps {
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/**
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* Get elements in set a that are not in set b
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*
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* @param {Object[]} a
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* @param {Object[]} b
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* @returns {Object[]}
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@ -137,6 +139,7 @@ class SetOps {
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/**
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* Get elements of each set that aren't in the other set.
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*
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* @param {Object[]} a
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* @param {Object[]} b
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* @return {Object[]}
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@ -147,6 +150,7 @@ class SetOps {
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}
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/**
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* Return the cartesian product of the two inputted sets.
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*
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* @param {Object[]} a
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* @param {Object[]} b
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@ -159,38 +163,39 @@ class SetOps {
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}
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/**
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* Return the power set of the inputted set.
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*
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* @param {Object[]} a
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* @returns {Object[]}
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*/
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runPowerSet(delimiter) {
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return function(a) {
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runPowerSet(delimiter, a) {
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// empty array items getting picked up
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a = a.filter(i => i.length);
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if (!a.length) {
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return [];
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}
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// empty array items getting picked up
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a = a.filter(i => i.length);
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if (!a.length) {
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return [];
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}
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/**
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* Decimal to binary function
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* @param {*} dec
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*/
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const toBinary = (dec) => (dec >>> 0).toString(2);
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const result = new Set();
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// Get the decimal number to make a binary as long as the input
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const maxBinaryValue = parseInt(Number(a.map(i => "1").reduce((p, c) => p + c)), 2);
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// Make an array of each binary number from 0 to maximum
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const binaries = [...Array(maxBinaryValue + 1).keys()]
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.map(toBinary)
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.map(i => i.padStart(toBinary(maxBinaryValue).length, "0"));
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/**
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*
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* @param {*} dec
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*/
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const toBinary = (dec) => (dec >>> 0).toString(2);
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const result = new Set();
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const maxBinaryValue = parseInt(Number(a.map(i => "1").reduce((p, c) => p + c)), 2);
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const binaries = [...Array(maxBinaryValue + 1).keys()]
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.map(toBinary)
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.map(i => i.padStart(toBinary(maxBinaryValue).length, "0"));
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// XOR the input with each binary to get each unique permutation
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binaries.forEach((binary) => {
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const split = binary.split("");
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result.add(a.filter((item, index) => split[index] === "1"));
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});
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binaries.forEach((binary) => {
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const split = binary.split("");
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result.add(a.filter((item, index) => split[index] === "1"));
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});
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// map for formatting & put in length order.
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return [...result].map(r => r.join(delimiter)).sort((a, b) => a.length - b.length);
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};
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// map for formatting & put in length order.
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return [...result].map(r => r.join(delimiter)).sort((a, b) => a.length - b.length);
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}
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}
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