ctf-writeup/IrisCTF 2023/babystrechy

babystrechy

More byte mean more secure

Although this is a web challenge, the script is ran directly with PHP because it doesn't need to have an HTML website attached. Run the command below to connect!

About the Challenge

We are given a PHP file like the code below

<?php
$password = exec("openssl rand -hex 64");

$stretched_password = "";
for($a = 0; $a < strlen($password); $a++) {
    for($b = 0; $b < 64; $b++)
        $stretched_password .= $password[$a];
}

echo "Fear my 4096 byte password!\n> ";

$h = password_hash($stretched_password, PASSWORD_DEFAULT);

while (FALSE !== ($line = fgets(STDIN))) {
    if(password_verify(trim($line), $h)) die(file_get_contents("flag"));
    echo "> ";
}
die("No!");

?>

So the code will generate a password of 64 hex characters

$password = exec("openssl rand -hex 64");

And then each character will be repeated up to 64 times

$stretched_password = "";
for($a = 0; $a < strlen($password); $a++) {
    for($b = 0; $b < 64; $b++)
        $stretched_password .= $password[$a];
}

After stretch the password, the stretched password will be hashed using password_hash function

$h = password_hash($stretched_password, PASSWORD_DEFAULT);

The code will check your input, if your input passes password_verify function, and then the code will print the flag

while (FALSE !== ($line = fgets(STDIN))) {
    if(password_verify(trim($line), $h)) die(file_get_contents("flag"));
    echo "> ";
}
die("No!");

How to Solve?

Simply by creating a python script to bruteforce the hash. You can check the code here. After running the code we will retrieve the flag

irisctf{truncation_silent_and_deadly}